flamingos-cant@feddit.uk to 196@lemmy.blahaj.zoneEnglish · 1 year agoSpectrum rulefeddit.ukimagemessage-square138linkfedilinkarrow-up1981arrow-down11
arrow-up1980arrow-down1imageSpectrum rulefeddit.ukflamingos-cant@feddit.uk to 196@lemmy.blahaj.zoneEnglish · 1 year agomessage-square138linkfedilink
minus-squareKogasa@programming.devlinkfedilinkarrow-up2·11 months agoIt’s required, but nontrivially so. It has been proven that ZF + dependent choice is consistent with the assumption that all sets of reals are Lebesgue measurable.
It’s required, but nontrivially so. It has been proven that ZF + dependent choice is consistent with the assumption that all sets of reals are Lebesgue measurable.