#You are an input. You have value! You matter!
if number % 2 == 0
return "number is even" (is_num_even = 1 or true)
else
return "number is odd" (is_num_even = 0 or false)
modulo
pseudocode:
if number % 2 == 0 return "number is even" (is_num_even = 1 or true) else return "number is odd" (is_num_even = 0 or false)
plus you’d want an input validation beforehand
who needs modulo when you can get less characters out of
while (number > 1) { number -= 2; } return number;
very efficient
edit: or theres the trusty iseven api
here is somewhat less:
return (number % 2) == 0;
return !(number & 1);
This is the way. Modulo takes too long to compute, bitwise compare should be a lot faster.
return !(number & 0x1);
oh shit yo
this comment chain is pretty awesome, I learned a lot from this thanks!
just check the last bit jesus christ, what is it with these expensive modulo operations?!
return !(n&1);
are the negative numbers all even?
Yes
🤦
#You are an input. You have value! You matter! if number % 2 == 0 return "number is even" (is_num_even = 1 or true) else return "number is odd" (is_num_even = 0 or false)
Am I doing it right? /S.
Don’t put nbsps in code blocks, they show up literally.
Name doesn’t check out.
John carmak posting
This code is terrible. If you input 10.66 it returns "number is odd
It should be:
if number % 2 == 0 return "number is even" (is_num_even = 1 or true) else return "number is not even" (is_num_even = 0 or false)
are u a wizard?