Day 6: Wait for It


Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ , pastebin, or github (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)

FAQ

  • @mykl@lemmy.world
    link
    fedilink
    4
    edit-2
    1 year ago

    Dart Solution

    I decided to use the quadratic formula to solve part 1 which slowed me down while I struggled to remember how it went, but meant that part 2 was a one line change.

    This year really is a roller coaster…

    int countGoodDistances(int time, int targetDistance) {
      var det = sqrt(time * time - 4 * targetDistance);
      return (((time + det) / 2).ceil() - 1) -
          (max(((time - det) / 2).floor(), 0) + 1) +
          1;
    }
    
    solve(List> data, [param]) {
      var distances = data.first
          .indices()
          .map((ix) => countGoodDistances(data[0][ix], data[1][ix]));
      return distances.reduce((s, t) => s * t);
    }
    
    getNums(l) => l.split(RegExp(r'\s+')).skip(1);
    
    part1(List lines) =>
        solve([for (var l in lines) getNums(l).map(int.parse).toList()]);
    
    part2(List lines) => solve([
          for (var l in lines) [int.parse(getNums(l).join(''))]
        ]);