@aburtang@lemmy.world to Programmer Humor@lemmy.ml • 3 days agoEvil Oneslemmy.worldimagemessage-square76fedilinkarrow-up1991arrow-down131
arrow-up1960arrow-down1imageEvil Oneslemmy.world@aburtang@lemmy.world to Programmer Humor@lemmy.ml • 3 days agomessage-square76fedilink
minus-squarepooberbee (they/she)linkfedilink1•3 days agoYeah, you would get a runtime error calling that member without checking that it exists.
minus-square@masterspace@lemmy.calinkfedilinkEnglish1•edit-21 day agoBecause that object is of a type where that member may or may not exist. That is literally the exact same behaviour as Java or C#. If I cast or type check it to make sure it’s of type Bar rather than checking for the member explicitly it still works: And when I cast it to Foo it throws a compile time error, not a runtime error:
Yeah, you would get a runtime error calling that member without checking that it exists.
Because that object is of a type where that member may or may not exist. That is literally the exact same behaviour as Java or C#.
If I cast or type check it to make sure it’s of type Bar rather than checking for the member explicitly it still works:
And when I cast it to Foo it throws a compile time error, not a runtime error: